India stopped Australia for 195 runs in the first innings

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In the first innings of the Melbourne Test match, India dismissed all the players of Australia for 195 runs in 72.3 overs.

This is the second match in a four-Test series. India lost the first Test match played in Adelaide. Today, India started well under Ajinkya Rahane’s captaincy.

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In the Test match being played at Melbourne Cricket Ground in Australia, Australia decided to bat first by winning the toss. From Australia, Marnus Laboshen scored the most 48 runs. Joe Burns and Steven Smith could not even open an account.

Jasprit Bumrah took the most wickets from India. Bumrah took four wickets for 56 runs in 16 overs. R Ashwin remained at number two. He took three wickets for 35 runs in 24 overs. Mohammad Siraj took two wickets.

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The opening of Australia’s Joe Burns and Matthew Wade soon shattered. In the fourth over itself, Joe Burns lost his wicket off Jasprit Bumrah. He was caught by Rishabh Pant and thus Australia’s first wicket fell on 10 runs. After this, Ravindra Jadeja caught the catch of Mathieu Wade in the thirteenth over off Ashwin.

Shubham Gill also ran to take the catch and finally hit Jadeja. But Jadeja did not let the ball fall and successfully took the catch. This catch of Jadeja on social media is being highly praised.

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After this Steve Smith came on the pitch but was caught by Pujara without scoring any runs in the 15th over. This was the second big wicket for Ashwin. By the 15th over, Australia had scored 38 runs for the loss of three wickets.

Rahane sent Travis back to the pavilion off Jaspreet Bumrah in the 42nd over. By 63 overs, Australia had scored 156 runs losing seven wickets.

In their first Test match, Shubham Gill and Mohammad Siraj have also opened the account. On the ball of Mohammad Siraj, Marnus Laboshen was caught by Shubham Gill and Australia lost their fifth wicket.

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